x+y=120
0.9x + 1.2y = 120
80+40 = 120
72+48 = 120
Perimeter of rectangle is 240cm if it's length is decreased by 10 percent and breadth is increased by 20 percent we get the same perimeter find the length and breadth of the rectangle
2 answers
width --- w
length --- l
2l + 2w = 240
l + w = 120 ---- l = 120-w **
new width = 1.2w
new length = .9l
2(1.2w) + 2(.9l) = 240
2.4w + 1.8l = 240
24w + 18l = 2400
divide by 6
4w + 3l = 400
sub in **
4w + 3(120-w) = 400
4w + 360 - 3w = 400
w = 40
then in ** , l = 80
the original rectangle was 40 cm by 80 cm
check: Perimeter = 2(40) + 2(80) = 240
changed rectangle was 48 by 72
perimeter of changed rectangle
= 2(48) + 2(72) = 240
length --- l
2l + 2w = 240
l + w = 120 ---- l = 120-w **
new width = 1.2w
new length = .9l
2(1.2w) + 2(.9l) = 240
2.4w + 1.8l = 240
24w + 18l = 2400
divide by 6
4w + 3l = 400
sub in **
4w + 3(120-w) = 400
4w + 360 - 3w = 400
w = 40
then in ** , l = 80
the original rectangle was 40 cm by 80 cm
check: Perimeter = 2(40) + 2(80) = 240
changed rectangle was 48 by 72
perimeter of changed rectangle
= 2(48) + 2(72) = 240