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Perform the operation(s) and simplify completely -(2x +6) (3x +4) = 5x^2 - 7xAsked by sayletyler
Perform the operation(s) and simplify completely. −(2x+6)(3x+4)+5x^2−7x
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Answered by
GPT-4o mini
Let's simplify the expression step by step:
We start with the expression:
\[
-(2x + 6)(3x + 4) + 5x^2 - 7x
\]
First, we need to expand \(-(2x + 6)(3x + 4)\):
\[
(2x + 6)(3x + 4) = 2x \cdot 3x + 2x \cdot 4 + 6 \cdot 3x + 6 \cdot 4
\]
Calculating each term:
- \(2x \cdot 3x = 6x^2\)
- \(2x \cdot 4 = 8x\)
- \(6 \cdot 3x = 18x\)
- \(6 \cdot 4 = 24\)
Now, combine these results:
\[
(2x + 6)(3x + 4) = 6x^2 + 8x + 18x + 24 = 6x^2 + 26x + 24
\]
Now, apply the negative sign:
\[
-(2x + 6)(3x + 4) = -6x^2 - 26x - 24
\]
Next, we combine this with the rest of the expression:
\[
-6x^2 - 26x - 24 + 5x^2 - 7x
\]
Combine like terms:
1. For \(x^2\) terms:
\(-6x^2 + 5x^2 = -x^2\)
2. For \(x\) terms:
\(-26x - 7x = -33x\)
3. The constant term is:
\(-24\)
Putting it all together gives:
\[
-x^2 - 33x - 24
\]
So, the fully simplified expression is:
\[
\boxed{-x^2 - 33x - 24}
\]
We start with the expression:
\[
-(2x + 6)(3x + 4) + 5x^2 - 7x
\]
First, we need to expand \(-(2x + 6)(3x + 4)\):
\[
(2x + 6)(3x + 4) = 2x \cdot 3x + 2x \cdot 4 + 6 \cdot 3x + 6 \cdot 4
\]
Calculating each term:
- \(2x \cdot 3x = 6x^2\)
- \(2x \cdot 4 = 8x\)
- \(6 \cdot 3x = 18x\)
- \(6 \cdot 4 = 24\)
Now, combine these results:
\[
(2x + 6)(3x + 4) = 6x^2 + 8x + 18x + 24 = 6x^2 + 26x + 24
\]
Now, apply the negative sign:
\[
-(2x + 6)(3x + 4) = -6x^2 - 26x - 24
\]
Next, we combine this with the rest of the expression:
\[
-6x^2 - 26x - 24 + 5x^2 - 7x
\]
Combine like terms:
1. For \(x^2\) terms:
\(-6x^2 + 5x^2 = -x^2\)
2. For \(x\) terms:
\(-26x - 7x = -33x\)
3. The constant term is:
\(-24\)
Putting it all together gives:
\[
-x^2 - 33x - 24
\]
So, the fully simplified expression is:
\[
\boxed{-x^2 - 33x - 24}
\]
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