did you notice that
z^2 - 64 = (z+8)(z-8) , the other two denominators?
so z^2 - 64 is the common denominator, and
[(z-1)(z+8) - (z+1)(z-8) + z-120]/(z-64)
= [z^2 + 7z - 8 - (z^2 - 7z - 8) + z-120]/z^2-64)
= (15z - 120]/(z^2-64)
= 15(z-8)/(z^2-64)
= 15/(x+8) , z ≠ 8
`Perform the indicated operations and simplify.
(z-1)/(z-8)-(z+1)/(z+8)+(z-120)/(z^2-64)
4 answers
Actually I kept t hinking the first two cancelled each other out because one was positive and the other negative. That's why I have been having such a hard time with this one. Thanks so much for your help.
Solve 6x^4-19x^2+10=0
I got
x=-0.816496581, 0.816496581
x=-1.58113883, 1.58113883
Is this correct? It just doesn't seem right to me.
I got
x=-0.816496581, 0.816496581
x=-1.58113883, 1.58113883
Is this correct? It just doesn't seem right to me.
I got the same answers
4 answers