•algebra - MathMate, Tuesday, June 14, 2011 at 10:45am
I have made a guess and put on the minimum parentheses for the problem to make sense. Do not forget to enclose numerators and denominators with parentheses when transcribing expressions from a book or other sources.
(y-4)/(y-9) - (y+1)/(y+9) + (y-99)/(y^2-81)
using (y-9)(y+9)=y²-81
=(y-4)/(y-9) - (y+1)/(y+9) + (y-99)/((y+9)(y-9))
=((y-4)(y+9)-(y+1)(y-9)+(y-99))/((y+9)(y-9))
=(y²+5y-36 - (y²-8y-9) + (y-99))/((y+9)(y-9))
=(14y-126)/((y+9)(y-9))
=14(y-9)/((y+9)(y-9))
=14/(y+9)
Perform the indicated operation
y/y-5+5/5-y
2 answers
I'm guessing you meant
y/(y-5)+5/(5-y)
= y/(y-5) - 5/(y-5)
= (y-5)/(y-5)
= 1
y/(y-5)+5/(5-y)
= y/(y-5) - 5/(y-5)
= (y-5)/(y-5)
= 1
1 answer