What in the world are you trying to type?
Type fractions like this (a+b)/(c+d)
Perform operation
3/ * 2a+2/
a²+a 6
4 answers
I have a feeling you meant to type
[3/(a^2 + a)][(2a + 2)/6]
= 3/((a(a+1))*(a(a+1))/6
= 1/a , a cannot be equal to -1
[3/(a^2 + a)][(2a + 2)/6]
= 3/((a(a+1))*(a(a+1))/6
= 1/a , a cannot be equal to -1
Perform operation
3/a^2 x 2a+2/6
3/a^2 x 2a+2/6
second last line should read
= 3/((a(a+1))*(2(a+1))/6
= 3/((a(a+1))*(2(a+1))/6