In the carnival game you're describing, participants roll a standard six-sided number cube (often referred to as a die). The faces of the die are labeled with the numbers 1 through 6.
To determine the chances of winning a prize, we need to identify the winning outcomes. According to your description, a player wins a prize if they roll a number greater than 4. The numbers greater than 4 on a six-sided die are:
- 5
- 6
So there are 2 winning outcomes (rolling a 5 or rolling a 6). The total number of possible outcomes when rolling the die is 6 (since it has six faces).
To find the probability of winning a prize, we can calculate it as follows:
\[ \text{Probability of winning} = \frac{\text{Number of winning outcomes}}{\text{Total number of outcomes}} = \frac{2}{6} = \frac{1}{3} \]
This means that there is a 1 in 3 chance, or approximately 33.33%, of winning a prize when playing the game.
If you have any more questions about the game or need further assistance, feel free to ask!
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