Pentane (C5H12) burns in oxygen to produce carbon dioxide and water.

Question

C5H12(g)+8O2(g)→5CO2(g)+6H2O(g)

Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield.

Answer 1

mols pentane = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols pentane to mols CO2.

Then g CO2 = mols CO2 x molar mass CO2 and this is the mass at 100% yield.

Mass CO2 at 58.0% yield is mass at 100% yield x 0.580 = ?

Answer 2

What was the answer exactly?

Answer 3

CO and H2O

Answer 4

Sodium bicarbonate in an reacts with hydrochloric acid to form carbon dioxide sodium chloride and water