To find the area of the cardboard in Pedro's model, we need to find the area of each face of the square pyramid and then sum them up.
The area of each triangular face is 1/2 * base * height.
For Pedro's model, the base of each triangular face is one edge of the square base, which is 5 inches long. The height of each triangular face is given as 4 inches.
So, the area of each triangular face is 1/2 * 5 in * 4 in = 10 square inches.
Since there are 4 triangular faces in a square pyramid, we can multiply the area of one triangular face by 4 to find the total area of the triangular faces.
Total area of the triangular faces = 10 sq in * 4 = 40 square inches.
Next, we need to find the area of the square base of the pyramid. The base is a square, so its area is just the length of one side squared. In this case, the length of one side of the square base is given as 5 inches.
Area of the square base = 5 in * 5 in = 25 square inches.
To find the total area of the cardboard in Pedro's model, we add the area of the triangular faces and the area of the square base.
Total area of the cardboard = Area of triangular faces + Area of square base
= 40 square inches + 25 square inches
= 65 square inches.
Therefore, the area of the cardboard in Pedro's model is 65 square inches.
Pedro uses cardboard to make a model of a square pyramid. The edges of the base of the model are 5 In.long. the height of each triangular face is 4 in. What is the area of the cardboard in Pedro's model? Show your work.
1 answer