Paying attention to radio and television commercials provides

Question

a. the most accurate information on competing products.
b. practice in careful listening.

Answer 1

b. practice in careful listening.

Answer 2

You are drawing a net that shows a rectangular prism with an area of 52 square feet. If two of the rectangles in the net are 4 ft.×3 ft., what is the value of the third measurement you need to know to have an area of 52 square feet?

Answer 3

We can start by finding the total area of all the rectangles in the net. Since two of the rectangles are 4 ft.×3 ft., their total area is:

2 × 4 ft. × 3 ft. = 24 square feet

Let's denote the third rectangle's dimensions as x ft. × y ft. Then, we know that the total area of the net is 52 square feet, so we can set up an equation:

24 + x y = 52

Solving for xy, we get:

xy = 52 - 24 = 28

Therefore, to find the value of the third measurement we need to know, we can solve for either x or y. Let's solve for x:

x y = 28
x = 28 / y

Now we just need to substitute this expression for x into one of the rectangle dimensions:

x ft. × 3 ft. = 4 ft. × 3 ft.

Substituting x = 28 / y, we get:

(28 / y) ft. × 3 ft. = 4 ft. × 3 ft.

Multiplying both sides by y/3, we get:

28 ft. = (4 ft. × y)

Dividing both sides by 4 ft., we get:

y = 7 ft.

Therefore, the dimensions of the third rectangle in the net are 28/7 ft. × 7 ft., or simplified, 4 ft. × 7 ft.