Paul and Peter picked eggs from conveyor belts, A and B, respectively at the same time. If Paul picked 36 eggs per minute and Peter picked 18 eggs per minute, there would be 144 eggs left on the Conveyor belt A, when all the eggs were picked from Conveyor belt B. If Peter picked 40 eggs per minute and Paul picked 20 eggs per minute, there would be 432 eggs left on Conveyor belt A when all the eggs were picked from Conveyor belt B. How many eggs were there on the 2 conveyor belts?

1 answer

Peter finishes first, so in the first case,
if it takes Peter x minutes at 18 eggs/min to clean belt B, then B has 18x eggs
so A has 36x+144 eggs

If it takes Peter y minutes at 40 eggs/min, then B had 40y eggs, so
18x = 40y
y = 9/20 x
and A had 20y+432 = 9x+432 eggs

36x+144 = 9x+432

see what you can do with that