so as I read it, five hours after the freight train leaves.
so the distance the passenger train travels is 3*VP=3((Vt+14)
distance the freight train travels is
5(Vt) But the distances are equal
5Vt=3Vt+42
vt=21 mph
vp=35
so recheck your math, especially what is 3 times 14
Passenger train leaves 2 hours after a freight train leaves. The freight train travels 14 mph slower than the passenger train. Find the rate of each train if the passenger train overtakes the freight train in 3 hours.
I did this :
5r=3(r+14)
5=3r+28
2r=28
Freight train =14 mph
Passenger = 28 mph
Can you please correct me I'm not quite sure how to do this problem
3 answers
The freight travels r mi/h.
The passenger train travels r+14 mi/h.
Df = Dp.
5r = 3(r+14)
5r = 3r + 42
r = 21 mi/h.
r+14 = 21 + 14 = 35 mi/h.
Laura, Your Eq is correct, but you made an error when solving it.
The passenger train travels r+14 mi/h.
Df = Dp.
5r = 3(r+14)
5r = 3r + 42
r = 21 mi/h.
r+14 = 21 + 14 = 35 mi/h.
Laura, Your Eq is correct, but you made an error when solving it.
Thank you for your feedback!
I have realized my mistakes
I have realized my mistakes