To raise the received level of your voice by 5.84 dB, the received intensity of your voice must be higher by a factor
10^(5.84/10)= 10^0.584 = 3.837
To acheieve this increase, the distance must decrease by a factor (because of the inverse square law of inteneity)
x = sqrt(3.837) = 1.959
That makes the new distance
1.65/1.959 = 0.842 m
For a review of the subject, see
http://en.wikipedia.org/wiki/Decibel
Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the background noise of the other partygoers. However, once you reach the level of yelling, the only way you can be heard is if you move closer to your listener, into the listener's �personal space.� Model the situation by replacing you with an isotropic point source of fixed power P and replacing your listener with a point that absorbs part of your sound waves. These points are initially separated by ri = 1.65 m. If the background noise increases by �� = 5.84 dB, the sound level at your listener must also increase. What separation rf is then required?
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