... if the vertical distance between the lid of the garbage can andthe runner’s point of release is 0.50m
h=gt²/2
t=sqrt(2h/g)=
sqrt(2•0.5/9.8) = 0.32 s
s=vt= 6.2•0.32 = 2 m
Participants in a road race take water from
a refreshment station and throw their
empty cups away farther down the course.
If a runner has a forward speed of 6.20 m/s,
how far in advance of a garbage pail
should he release his water cup if the
vertical distance between the lid of the
garbage can and the runner’s point of
Answer is 2.0m
please show steps and explain thank you
1 answer