Participants from the National Health and Nutrition Examination Survey, 2003–2004, had a mean BMI of 28.3 with a standard deviation of 6.0. Assuming BMI is normally distributed, what proportion of the participants had a BMI measure over 35?

Question

Participants from the National Health and Nutrition Examination Survey, 2003–2004, had a mean BMI of 28.3 with a standard deviation of 6.0.  Assuming BMI is normally distributed, what proportion of the participants had a BMI measure over 35?

PsyDAG · Answer

Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

craig · Answer

78