Question

Part A:

How can the following equation be re-written if you factor out the Greatest Common Factor?

3x2βˆ’15x=0
3
π‘₯
2
βˆ’
15
π‘₯
=
0


(1 point)
Responses

3x(x+5)=0
3
π‘₯
(
π‘₯
+
5
)
=
0
3 x open paren x plus 5 close paren is equal to 0

3x(xβˆ’5)=0
3
π‘₯
(
π‘₯
βˆ’
5
)
=
0
3 x open paren x minus 5 close paren is equal to 0

3x(xβˆ’15)=0
3
π‘₯
(
π‘₯
βˆ’
15
)
=
0
3 x open paren x minus 15 close paren is equal to 0

5x(xβˆ’5)=0
5
π‘₯
(
π‘₯
βˆ’
5
)
=
0
5 x open paren x minus 5 close paren is equal to 0
Question 2
Part B:

What would the two solutions be?

(1 point)
Responses

x=0 and x=5
π‘₯
=
0


π‘Ž
𝑛
𝑑

π‘₯
=
5
x=0 and x=5
π‘₯
=
0


π‘Ž
𝑛
𝑑

π‘₯
=
5

x=0
π‘₯
=
0

x=0
π‘₯
=
0


x=5
π‘₯
=
5
x is equal to 5

x=0 and x=βˆ’5

Answers

There are no human answers yet.
Answered by GPT-4o mini
**Part A:**

To factor out the Greatest Common Factor (GCF) from the equation \(3x^2 - 15x = 0\):

1. Identify the GCF of the terms \(3x^2\) and \(15x\). The GCF is \(3x\).
2. Factor out \(3x\):

\[
3x(x - 5) = 0
\]

So, the correct response is:
**3x(xβˆ’5)=0**.

---

**Part B:**

To find the solutions of the equation \(3x(x - 5) = 0\), we set each factor equal to zero:

1. \(3x = 0\) gives \(x = 0\).
2. \(x - 5 = 0\) gives \(x = 5\).

Thus, the two solutions are:

**x=0 and x=5**.

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