Question
Part A:
How can the following equation be re-written if you factor out the Greatest Common Factor?
3x2β15x=0
3
π₯
2
β
15
π₯
=
0
(1 point)
Responses
3x(x+5)=0
3
π₯
(
π₯
+
5
)
=
0
3 x open paren x plus 5 close paren is equal to 0
3x(xβ5)=0
3
π₯
(
π₯
β
5
)
=
0
3 x open paren x minus 5 close paren is equal to 0
3x(xβ15)=0
3
π₯
(
π₯
β
15
)
=
0
3 x open paren x minus 15 close paren is equal to 0
5x(xβ5)=0
5
π₯
(
π₯
β
5
)
=
0
5 x open paren x minus 5 close paren is equal to 0
Question 2
Part B:
What would the two solutions be?
(1 point)
Responses
x=0 and x=5
π₯
=
0
π
π
π
π₯
=
5
x=0 and x=5
π₯
=
0
π
π
π
π₯
=
5
x=0
π₯
=
0
x=0
π₯
=
0
x=5
π₯
=
5
x is equal to 5
x=0 and x=β5
How can the following equation be re-written if you factor out the Greatest Common Factor?
3x2β15x=0
3
π₯
2
β
15
π₯
=
0
(1 point)
Responses
3x(x+5)=0
3
π₯
(
π₯
+
5
)
=
0
3 x open paren x plus 5 close paren is equal to 0
3x(xβ5)=0
3
π₯
(
π₯
β
5
)
=
0
3 x open paren x minus 5 close paren is equal to 0
3x(xβ15)=0
3
π₯
(
π₯
β
15
)
=
0
3 x open paren x minus 15 close paren is equal to 0
5x(xβ5)=0
5
π₯
(
π₯
β
5
)
=
0
5 x open paren x minus 5 close paren is equal to 0
Question 2
Part B:
What would the two solutions be?
(1 point)
Responses
x=0 and x=5
π₯
=
0
π
π
π
π₯
=
5
x=0 and x=5
π₯
=
0
π
π
π
π₯
=
5
x=0
π₯
=
0
x=0
π₯
=
0
x=5
π₯
=
5
x is equal to 5
x=0 and x=β5
Answers
There are no human answers yet.
Answered by
GPT-4o mini
**Part A:**
To factor out the Greatest Common Factor (GCF) from the equation \(3x^2 - 15x = 0\):
1. Identify the GCF of the terms \(3x^2\) and \(15x\). The GCF is \(3x\).
2. Factor out \(3x\):
\[
3x(x - 5) = 0
\]
So, the correct response is:
**3x(xβ5)=0**.
---
**Part B:**
To find the solutions of the equation \(3x(x - 5) = 0\), we set each factor equal to zero:
1. \(3x = 0\) gives \(x = 0\).
2. \(x - 5 = 0\) gives \(x = 5\).
Thus, the two solutions are:
**x=0 and x=5**.
To factor out the Greatest Common Factor (GCF) from the equation \(3x^2 - 15x = 0\):
1. Identify the GCF of the terms \(3x^2\) and \(15x\). The GCF is \(3x\).
2. Factor out \(3x\):
\[
3x(x - 5) = 0
\]
So, the correct response is:
**3x(xβ5)=0**.
---
**Part B:**
To find the solutions of the equation \(3x(x - 5) = 0\), we set each factor equal to zero:
1. \(3x = 0\) gives \(x = 0\).
2. \(x - 5 = 0\) gives \(x = 5\).
Thus, the two solutions are:
**x=0 and x=5**.
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