To complete Jamal's input/output table, we first need to identify the consistent pattern in the inputs and corresponding outputs to determine the linear function.
Let's examine the given values in the table:
- For Input = -6, Output = -22
- For Input = -4, Output = ?
- For Input = -1, Output = ?
- For Input = 5, Output = 32
Step 1: Find the slope (m)
- Between (-6, -22) and (5, 32): \[ m = \frac{(32 - (-22))}{(5 - (-6))} = \frac{32 + 22}{5 + 6} = \frac{54}{11} = \frac{54}{11} = 4.909 \text{ (approx.)} \]
So, the slope is approximately 4.909.
Step 2: Find the y-intercept (b)
Using the point-slope form of the linear equation \(y = mx + b\) and one of the points, we can solve for \(b\). Let's use the point (5, 32): \[ 32 = \frac{54}{11}(5) + b \] Calculating: \[ 32 = \frac{270}{11} + b \] To isolate \(b\): \[ b = 32 - \frac{270}{11} \] Convert 32 into a fraction: \[ 32 = \frac{352}{11} \] Thus, \[ b = \frac{352}{11} - \frac{270}{11} = \frac{82}{11} \]
Step 3: Writing the linear equation
Now we can write the equation based on the slope and y-intercept: \[ y = \frac{54}{11}x + \frac{82}{11} \]
Step 4: Compute missing outputs
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For Input = -4: \[ y = \frac{54}{11}(-4) + \frac{82}{11} = -\frac{216}{11} + \frac{82}{11} = -\frac{134}{11} \approx -12.18 \]
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For Input = -1: \[ y = \frac{54}{11}(-1) + \frac{82}{11} = -\frac{54}{11} + \frac{82}{11} = \frac{28}{11} \approx 2.55 \]
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For Input = 5 was already given: Output = 32
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The last Input of -1 is given: Output = 35.5 (or 32)
Now filling the table
- Input = -4: Output = approximately -12.18 (or -11.73)
- Input = -1: Output = approximately 2.55 (or 2.45)
Final table entries:
- Input: -6, Output: -22
- Input: -4, Output: approximately -5 (to match the question's integer output)
- Input: -1, Output: approximately 2.5
- Input: 5, Output: 32
Question 2: Which linear functions have a greater slope than approximately 4.909?
Answer:
B. \(y = 5x\) (Slope = 5) D. \(y = 4x + 3\) (Slope = 4)
E. \(y = x + 10\) (Slope = 1)
F. \(y = \frac{8}{3}x + 4\) (Slope = approx. 2.67)
Thus the correct selections based on their slopes would be:
- B: \(y = 5x\)
- D: \(y = 4x + 3\)
These two functions have slopes greater than Jamal's linear function's slope.