Part 1: To set up the cost of ordering "c" corn dogs and "f" funnel cakes as an algebraic expression, we can multiply the cost of one corn dog ($2.75) by the number of corn dogs ordered ("c") and multiply the cost of one funnel cake ($3.50) by the number of funnel cakes ordered ("f"). The algebraic expression would be:
Cost = (2.75 * c) + (3.50 * f)
Part 2: To find out how much it would cost altogether for you and your three friends to order 2 corn dogs and 1 funnel cake each, we need to substitute the values into the algebraic expression.
Cost = (2.75 * 2) + (3.50 * 1)
Cost = 5.50 + 3.50
Cost = 9.00
Therefore, it would cost $9.00 altogether for you and your three friends to order 2 corn dogs and 1 funnel cake each.
Part 3: In part 2, I substituted the values of 2 for "c" (the number of corn dogs ordered) and 1 for "f" (the number of funnel cakes ordered) into the algebraic expression. By multiplying the cost of one corn dog ($2.75) by the number of corn dogs ordered (2) and multiplying the cost of one funnel cake ($3.50) by the number of funnel cakes ordered (1), I found the individual costs. Adding up the individual costs, I determined that it would cost $9.00 altogether.
Part 1.At the state fair it costs $2.75 for a corn dog and $3.50 for a funnel cake. How much would it cost for you to order “c” corndogs and “f” funnel cakes? Show how to set this up as an algebraic expression.
Part 2. You and your three friends want to order 2 corndogs and 1 funnel cake each. Solve to find out how much it would cost all together.
Part 3 explain how you solved part 2
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