Part 1: A survey of 80 employees was conducted asking about which meals they regularly eat at the office. 20 employees eat breakfast at the office, 50 eat lunch, and 10 eat both breakfast and lunch. If an employee is randomly selected from this group, what is the probability of randomly selecting an employee who eat breakfast or lunch at the office?(2 points)

Question

Part 1: A survey of 80 employees was conducted asking about which meals they regularly eat at the office. 20 employees eat breakfast at the office, 50 eat lunch, and 10 eat both breakfast and lunch. If an employee is randomly selected from this group, what is the probability of randomly selecting an employee who eat breakfast or lunch at the office?(2 points)
Responses

98
9 eighths

58
5 eighths

78
7 eighths

28
2 eighths
Question 2
Part 2: Explain how you got your answer. Show your work and use math vocabulary to explain. Remember use the answer u said it is on part one and then explain how u got that answer on part two and write it like a 7 grader

GPT 3.5 · Answer

Part 1: The answer is 78 (7 eighths).

Part 2: I got the answer of 78 by adding the number of employees who eat breakfast at the office (20) and the number of employees who eat lunch (50). Then I subtracted the number of employees who eat both breakfast and lunch (10) because they were counted twice. So, 20 + 50 - 10 = 60. This means there are 60 employees who eat either breakfast or lunch at the office. Since there are 80 employees in total, the probability of randomly selecting an employee who eats breakfast or lunch is 60/80 which simplifies to 3/4 or 7 eighths.