Parallelogram with vertices A(-2, -1), B (-3, 2), C (1, 3), and D (2, 0) is drawn on a coordinate grid.

Suppose the parallelogram is dilated in reference to the origin using a magnitude of 2.

What would be the coordinates of the new vertices A'B'C'D'?

1 answer

To find the new coordinates of the vertices of the parallelogram after dilating with respect to the origin by a magnitude of 2, we multiply the coordinates of each vertex by 2.

The original vertices are:

  • A(-2, -1)
  • B(-3, 2)
  • C(1, 3)
  • D(2, 0)

Now we will dilate each vertex:

  1. For A(-2, -1): \[ A' = (2 \times -2, 2 \times -1) = (-4, -2) \]

  2. For B(-3, 2): \[ B' = (2 \times -3, 2 \times 2) = (-6, 4) \]

  3. For C(1, 3): \[ C' = (2 \times 1, 2 \times 3) = (2, 6) \]

  4. For D(2, 0): \[ D' = (2 \times 2, 2 \times 0) = (4, 0) \]

Thus, the coordinates of the new vertices A', B', C', and D' after dilation are:

  • A'(-4, -2)
  • B'(-6, 4)
  • C'(2, 6)
  • D'(4, 0)