To find the total length of diagonal \( BD \) in kite \( ABCD \), we know that the diagonals of a kite intersect at right angles and the shorter diagonal is bisected by the longer diagonal. Since \( BE \) and \( DE \) are segments of the diagonal \( BD \) with \( BE = x + 3 \) and \( DE = 4x \), we can express the total length of \( BD \) as:
\[ BD = BE + DE = (x + 3) + (4x) \]
This simplifies to:
\[ BD = 5x + 3 \]
To find the total length of \( BD \), we need to set the two segments equal, since point \( E \) is the midpoint of \( BD \). This means:
\[ BE = DE \] which gives us:
\[ x + 3 = 4x \]
Solving for \( x \):
- Subtract \( x \) from both sides: \[ 3 = 3x \]
- Divide by 3: \[ x = 1 \]
Now, substituting back into \( BE \) and \( DE \):
- \( BE = x + 3 = 1 + 3 = 4 \)
- \( DE = 4x = 4 \cdot 1 = 4 \)
Thus, the total length of \( BD \) is:
\[ BD = BE + DE = 4 + 4 = 8 \]
Therefore, the total length of \( BD \) is:
8