(f◦g)(x)
f(x) = 3x
f(g) = 3g
but, g = 3x^2-2x+3
so, f(g) = 3(3x)^2 - 2(3x) + 3 = 9x^2 - 6x + 3
similarly, for (g◦f)(x)
g(f) = 3f^2 - 2f + 3
= 3(3x)^2 - 2(3x) + 3 = 27x^2 - 6x + 3
Pair of functions fx=3x and g(x) =3x^2-2x+3 find the following (f◦g)(x=)
2 answers
strange typo, but correct answer
f(g) = 3(3x^2 - 2x + 3) = 9x^2 - 6x + 3
f(g) = 3(3x^2 - 2x + 3) = 9x^2 - 6x + 3