p=3s
s=2m
p-(x+y) = s+x
p-(x+y) = m+y
If p gives away 1/2 of his eggs,
1/6 to s and 1/3 to m, then
Pablo has p/2
Sofia has p/3 + p/6 = p/2
Mia has p/6 + p/3 = p/2
Pablo, Sofia, and Mia got some candy eggs at a party. Pablo had three times as many eggs as Sofia, and Sofia had twice as many eggs as Mia. Pablo decides
to give some of his eggs to Sofia and Mia so that all three will have the same number of eggs. What fraction of his eggs should Pablo give to Sofia?
3 answers
Assign a variable to the number of eggs Mia has, say mm. Then, because we are given that Sofia has twice the number of eggs Mia has, Sofia has 2m2m eggs, and Pablo, having three times the number of eggs as Sofia, has 6m6m eggs. For them to all have the same number of eggs, they must each have m+2m+6m3=3mm+2m+6m3=3m eggs. This means Pablo must give 2m2m eggs to Mia and a mm eggs to Sofia, so the answer is m6m=(B) 1/6
i dont care