P4 + 6 Br2 -> 4PBr3

Question

In a particular reaction, 20 grams of phosphorus P4, is combined with 50mL liquid bromine ( Density= 2.93 g/ml)
1) Calculate the mass of product in grams for each of the reactants
2) Limiting reagant and Mass Maximum mass of PBr3

so for 1) I converted 20g P4 to gPBr3
and 2.93gBr2 to gBPr3.
2) Limiting reagant will be Br2 cause its the lowest number
The maximum mass will be the outcome of conversions of both P4 and Br2 to PBr3 and add them together?

Answer 1

Not so.
mols P4 = 20/molar mass P4 = ?
mols Pbr3 = ?mol P4 x (4 mols PBr3/1 mol P4) = ?

For grams Br2, it isn't 2.93.
mass Br2 = volume x density = 50 mL x 2.93 g/mL = ?
Then mols Br2 = g/molar mass = ?
Convert mols Br2, as above, to mols PBr3 . The smaller number will be the correct value to chose for mols PBr3 produced and the reagent (P4 or Br2) creating that smaller value will be the limiting regent.
Then mass PBr3 = smaller mols PBr3 x molar mass PBr3. .

Answer 2

i want to no bout what kind of chemical reaction it has