p varies partly as q and partly as the square of r. when p=6, q=8, r=4 and when p=10, q=12, r=5

A)Find the value of p when q=15, r=25

1 answer

To find the value of p when q=15 and r=25, we need to find the constant of proportionality relating p, q, and r using the given information.

We are told that p varies partly as q and partly as the square of r. This can be represented as:

p = k * q * r^2

where k is the constant of proportionality.

We can solve for k by plugging in the values of p, q, and r from the first set of given information (p=6, q=8, r=4):

6 = k * 8 * 4^2
6 = k * 8 * 16
6 = k * 128

Dividing both sides by 128:

k = 6/128
k ≈ 0.046875

Now that we have the value of k, we can use it to find the value of p when q=15 and r=25:

p = 0.046875 * 15 * 25^2
p = 0.046875 * 15 * 625
p = 34.375

Therefore, when q=15 and r=25, p is approximately equal to 34.375.