P(t)=1000/1+9e-0.7t'

Question

What will be the fish population P after 2 years?

Answer 1

To find the fish population after 2 years, we need to substitute t=2 in the given logistic growth model equation:

P(2) = 1000 / (1 + 9e^(-0.7*2))

P(2) = 1000 / (1 + 9e^(-1.4))

P(2) = 1000 / (1 + 9*0.2466) [using e^(-1.4) = 0.2466]

P(2) = 1000 / (1 + 2.2194)

P(2) = 1000 / 3.2194

P(2) ≈ 310.2

Therefore, the fish population after 2 years is approximately 310.2.