P, Q and R are points in the same horizontal plan. The bearing Q from P is 160 degrees and bearing of R from 050 degrees. If /PQ/= 6m and /QR/= 4m, find the /PR/ and bearing of R from P, correct to the nearest degree

Answer 1

Draw the diagram.
Use the law of cosines to get PR
Now you have a triangle RPQ
Then you can use either the law of cosines or sines to get the angle at P. The bearing of R from P will be 160+that angle

Answer 2

PR = PQ + QR.
PR = 6m[160o] + 4m[50o],
X = 6*sin160 + 4*sin50 = 5.12 m.
Y = 6*Cos160 + 4*Cos50 = -3.07 m.
PR = 5.12 - 3.07i = 5.97m[-59o] = 5.97m[121o] CW.