P is 49km away from q on a bearing of 135°.z is 64km away from R on a bearing of 225°find the distance of z from q and bearing of z from q
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I need an answer I don't no how to solve it
since you have not given any relation between PQ and ZR there is no way to figure this out.
If you mean Z is 64km from P:
ZQ = QP + PZ.
ZQ = 49[135o] + 64[225o],
X = 49*sin135 + 64*sin225 = -10.61 km.
Y = 49*Cos135 + 64*Cos225 = -79.90 km.
ZQ = -10.61 - 79.9i = 80.6km[7.56o] W. of S. = 80.6km[187.6o] CW.
ZQ = QP + PZ.
ZQ = 49[135o] + 64[225o],
X = 49*sin135 + 64*sin225 = -10.61 km.
Y = 49*Cos135 + 64*Cos225 = -79.90 km.
ZQ = -10.61 - 79.9i = 80.6km[7.56o] W. of S. = 80.6km[187.6o] CW.
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