QR/12 = cot21°
PR/12 = cot35°
PQ^2 = QR^2 + PR^2 - 2*QR*PR*cos30°
So, now we know that
QR = 31.26, PR = 17.14, PQ = 18.52
So, the bearing of P from Q is 162.53°
P and Q are two observation post on the same horizontal ground as the foot R of a vertical pole RT of height 12m. From R, the bearing of P and Q are 195 and 225 degrees respectively, the angles of elevation of T from P and Q are 35 and 21 degrees respectively. Calculate the distance of PQ and the bearing of P from Q
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