P + 5C2H5OH + 5/2 I2 ---> 5C2H5I + H3PO4 + H2O

m(P)=4.14g
m(C2H5OH)= 27.5g
m(I2)=63.5g
m(C2H5I)= 73g

Whats the percent yield of the reaction?
(Can someone more precisely explain how to solve the problem please)

2 answers

How do you mean "more precisely"? Has it been explained before. What did you not understand.
DrBob222 more precisely how to find the limiting reagent on this one, and what to do next please