Asked by Stella
P= 12e^(-0.02t)
What is the growth rate?
I thought it would be -1.98% because I punched in the e^-0.02 part and got .98 something and then that minus 1 is r so I got -1.98.
What is the growth rate?
I thought it would be -1.98% because I punched in the e^-0.02 part and got .98 something and then that minus 1 is r so I got -1.98.
Answers
Answered by
Damon
for exponential growth (continuous compounding)
amount = original * e^rt
rate = -.02 or -2 percent
for example if you have ten dollars
then after one year you will have
10 e^-.02
= 10(.980298) = nine dollars and eighty cents
so each year multiply by .98
NOT 1.98
BUT that is an approximation
It is really .980298 etc
but growth rate is negative 2%
amount = original * e^rt
rate = -.02 or -2 percent
for example if you have ten dollars
then after one year you will have
10 e^-.02
= 10(.980298) = nine dollars and eighty cents
so each year multiply by .98
NOT 1.98
BUT that is an approximation
It is really .980298 etc
but growth rate is negative 2%
Answered by
Stella
Thank you!
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