How many mols is 1.64 grams?
K = 39
Cl = 35.5
O3 = 3*16 = 48
so a mol is 122.5 grams
so we have 1.64/122.5 = .0134 mols KClO3
for every 2 mols KClO3 I get 3 mols O2
.0134 * 3/2 = .0201 mols O2
now at stp that is 22.4 * .0201 = .45 liters of O2
you do the PV=nRT to get volume of .0201 mols at your pressure and temperature
Oxygen gas can be generated by heating KClO3 in the presence of some MnO2.
2KClO3 → 2KCl + 3O2
If all the KClO3 in a mixture containing 1.64 g KClO3 and 0.20 g MnO2 is decomposed, how many liters of O2 gas will be generated at T = 23.0°C and P = 767.9 torr?
1 answer
1 answer