Convert milligrams of oxygen to grams, then divide by f.wt O2 (=32) => moles O2. Then apply equation ratios...
15 moles O2 => 6 moles HOH
N-moles O2 => x
(15/N-molesO2) = (6/X)
Solve for X and then multiply by f.wt. HOH (=18g/mole) => grams HOH.
Oxygen gas and aqueous benzoic acid react to form carbon dioxide gas and water gas. Determine the mass of water in grams if 5.43×104 milligrams of oxygen reacts with an excess of benzoic acid.
I balanced the equation to
2C7H6O2+15O2=14CO2+6H2O
1 answer
1 answer