Asked by mathew
oxidation state of nitrogen in n2h4
Answers
Answered by
bobpursley
It depends on the rules for assigning oxidation numbers.
My rule for Hydrogen is :
# Hydrogen has an oxidation state of +1 except when bonded to more electropositive elements such as sodium, aluminium, and boron, as in NaH, NaBH4, LiAlH4, where each H has an oxidation state of -1.\
So here, N2H4 means nitrogen is the more electropositive, so H is -1, leaving N to be +2
N is +2
My rule for Hydrogen is :
# Hydrogen has an oxidation state of +1 except when bonded to more electropositive elements such as sodium, aluminium, and boron, as in NaH, NaBH4, LiAlH4, where each H has an oxidation state of -1.\
So here, N2H4 means nitrogen is the more electropositive, so H is -1, leaving N to be +2
N is +2
Answered by
Arslan khan
In this compound N2H4 the oxidation number on each atom of nitrogen is -2 and oxidation number on each hydrogen atom is +1 so the over all on nitrogen atoms has -4 and on hydrogen atoms is +4 so overall compound is neutral .
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.