Over the summer, you text a bunch. Let’s say you make 50 texts every 2 days. The graph represents the scenario. (4 points) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Fill in the missing parts of the table: x - # of days 0 a. 7 b. y - # of texts c. 75 d. 300

Question

Over the summer, you text a bunch. Let’s say you make 50 texts every 2 days. The graph represents the scenario. (4 points) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Fill in the missing parts of the table: x - # of days 0 a. 7 b. y - # of texts c. 75 d. 300
The graph for water used is 10,20,30,40,50on the left and on the bottom is time going from 2,4,6,8,10
The points are at (5,1),(10,2),(15,3), (35,7),(50,10)

a linear relationship,y=5x,a constant rate of change, 1/2, 1/5, the points are connected,5y=x,5,linear with a y-intercept at(0,0),1/2=x,2y=x,2,1

GPT-4o mini · Answer

Based on the scenario you've provided, it looks like you're trying to fill in a table where 'x' represents the number of days and 'y' represents the number of texts sent during that period. Let's deduce the values step by step.

You mentioned that you send 50 texts every 2 days. Therefore, the rate of text sending can be calculated as follows:

Determine Rate of Texts per Day:
- 50 texts every 2 days means: \[ \text{Rate} = \frac{50 \text{ texts}}{2 \text{ days}} = 25 \text{ texts per day} \]
Fill in the Table Entries:
- For \( x = 0 \) days: \( y = 25 \times 0 = 0 \)
- For \( x = 2 \) days (2 days): \( y = 25 \times 2 = 50 \)
- For \( x = 4 \) days (4 days): \( y = 25 \times 4 = 100 \)
- For \( x = 6 \) days (6 days): \( y = 25 \times 6 = 150 \)
- For \( x = 8 \) days (8 days): \( y = 25 \times 8 = 200 \)
- For \( x = 10 \) days (10 days): \( y = 25 \times 10 = 250 \)
- Continuing this for \( x=12 \), \( x=14 \), \( x=16 \), \( x=18 \), \( x=20 \) days:
  - \( x = 12 \): \( y = 300 \)
  - \( x = 14 \): \( y = 350 \)
  - \( x = 16 \): \( y = 400 \)
  - \( x = 18 \): \( y = 450 \)
  - \( x = 20 \): \( y = 500 \)
Identifying Missing Values in the table (since provided values need to fill in):
- a: In the entries, you have a as the value of days, which based on the above findings can be filled:
  - For x = 4, it corresponds to y = 100
- b: Given the context, let's say the missing value for b is referring to x = 8 days, which corresponds to y = 200.
- c: The missing value for c is thus 0 for x=0.
- d: The value for d would be the value at 60 days as per the relation we've built, thus y = 25 * 12 = 300.

Thus the filled table should look as:

| x - # of days | y - # of texts | |---------------|-----------------| | 0 | 0 | | 2 | 50 | | 4 | 100 | | 6 | 150 | | 8 | 200 | | 10 | 250 | | 12 | 300 |

With the responses:

a = 4,
b = 8,
c = 0,
d = 300.

For the response selection related options such as "linear relationship," the equation of the line reflecting the rate would be \( y = 25x \), which is indeed a linear relationship with a slope of 25, iterating through the correct values should maintain this structure.