the amplitude is (87-73)/2 = 7
the center line is (87+73)/2 = 80
y = 7sin(k(x-h))+80
since y(8) = 0,
y = 7sin(k(x-8))+80
since the period is 24 hours, 2π/k=24, so k = π/12
y = 7sin(π/12 (x-8))+80
so, when is y=77?
Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature varies between 73 and 87 degrees during the day and the average daily temperature first occurs at 8 AM. How many hours after midnight, to two decimal places, does the temperature first reach 77 degrees?
2 answers
Substitute y for 77 Get sin by itself, divide by 7 on both sides
Consider everything in the parenthesis of sin as theta, then solve using sin^-1
77 = 7sin(theta)+80
-3 = 7sin(theta)
-3/7 = sin(theta)
or
sin^-1(-3/7)=theta
take the answer to sin^-1(3/7) and then operate on it with what theta was , (π/12 (x-8))
get x by itself, multiply by the reciprocal 12/π to both sides and then add 8.
That should be your answer. Hope that helped.
Consider everything in the parenthesis of sin as theta, then solve using sin^-1
77 = 7sin(theta)+80
-3 = 7sin(theta)
-3/7 = sin(theta)
or
sin^-1(-3/7)=theta
take the answer to sin^-1(3/7) and then operate on it with what theta was , (π/12 (x-8))
get x by itself, multiply by the reciprocal 12/π to both sides and then add 8.
That should be your answer. Hope that helped.