Our teacher asked, a few weeks ago, for us to find the pH of 7.65 E-11 M HClO3. We were told that we couldn't find the pH simply by -log[7.65E-11]. He said that we had to account for the water somehow [I think we had to do something with the number 1.0 E-7]. Does anyone know what exactly I have to do with the water [I don't have it written down, but I have that the pH= 7.00] and why/when do I have to do this?
Since the H+ contribution is greater than that of the acid, yes, you have to add them:
[H+]= .000 000 1 + .000 000 000 0765
add them, then do the log. The reason that the log is close to seven is that the water domintes as the contribution to the hydrogen ion.
5 answers