The correct answer is A. 0.25x + 3 ≤ 10; 28 games.
To find the maximum number of games that can be played, we need to set up an inequality representing the amount of money available and the cost of the games. Let x represent the number of games played.
We have $10 available, so the amount of money spent on games is 0.25x. The admission fee of $3 is subtracted from the total amount of money spent. Thus, the inequality can be written as:
0.25x + 3 ≤ 10
To solve this inequality, we subtract 3 from both sides:
0.25x ≤ 7
Next, we divide both sides by 0.25:
x ≤ 28
Therefore, the maximum number of games that can be played with $10 is 28 games.
Our middle school is having a fall carnival. Admission into the carnival is $3 and each game inside the carnival costs $.25. Write an inequality that represents the possible number of games that can be played having $10. What is the maximum number of games that can be played? (1 point)
A. 0.25x + 3 ≤ 10; 28 games
B. 0.25x - 3 ≤ 10; 52 games
C. 0.25x - 3 < 10; 52 games
D. 0.25x + 3 < 10; 28 games
1 answer
3 answers