The total number of ways to pick 2 games out of 52 is given by the combination formula:
C(52,2) = 52! / (2!(52-2)!) = 52 * 51 / 2 = 1326
The number of ways to pick 2 games against the Snakes out of the 5 games against the Snakes is given by the combination formula:
C(5,2) = 5! / (2!(5-2)!) = 5 * 4 / 2 = 10
Therefore, the probability of picking 2 games against the Snakes out of all possible combinations is:
10 / 1326 = 10/1326 = 5/663
our employer is offering free tickets for two baseball games. They play
52
52 home games and
5
5 of them are against the Snakes. The tickets are randomly given out. What is the probability that both are games are against the Snakes? Write your answer as a fraction. You do not need to simplify.
1 answer
1 answer