Organic chemistry:
an attempt at synthesizing a certain optically active compound resulted in a mixture of its enantiomers. The mixture had an observed specific rotation of 11.0 degrees. If it is known that the specific rotation of the R enantiomer is -33.6 degrees, determine the percent of each enantiomer in the mixture.
So i have the equation set up:
11= x(-33.6) +(1-x)(spec. rot of S)
but how do i solve for x when the specific rotation of S is unknown?
2 answers
If the R enantiomer is -33.6, then the S enantiomer must be + 33.6? right?
Yes! S enantiomer would be +33.6
1 answer