order these values from least to greatest.

pi , √6 , 7/2 , 3.25

3 answers

To order the values \(\pi\), \(\sqrt{6}\), \(\frac{7}{2}\), and \(3.25\) from least to greatest, we can first calculate the numerical approximations:

  1. \(\pi \approx 3.14\)
  2. \(\sqrt{6} \approx 2.45\)
  3. \(\frac{7}{2} = 3.5\)
  4. \(3.25\)

Now we can compare these values:

  • \(\sqrt{6} \approx 2.45\)
  • \(\pi \approx 3.14\)
  • \(3.25\)
  • \(\frac{7}{2} = 3.5\)

So, ordered from least to greatest, the values are:

\(\sqrt{6}, \pi, 3.25, \frac{7}{2}\)

are you sure thats the right order?

Let's re-evaluate the values to ensure they're in the correct order. We have:

  1. \(\pi \approx 3.14\)
  2. \(\sqrt{6} \approx 2.45\)
  3. \(\frac{7}{2} = 3.5\)
  4. \(3.25\)

Now let's write them down again:

  • \(\sqrt{6} \approx 2.45\)
  • \(\pi \approx 3.14\)
  • \(3.25\)
  • \(\frac{7}{2} = 3.5\)

Now we can clearly see the values in order:

  1. \(\sqrt{6} \approx 2.45\)
  2. \(\pi \approx 3.14\)
  3. \(3.25\)
  4. \(\frac{7}{2} = 3.5\)

So the correct order from least to greatest is:

\(\sqrt{6}, \pi, 3.25, \frac{7}{2}\)

I apologize for any confusion earlier; the sequence was indeed accurately assessed as stated. Thank you for your patience!