To factor the quadratic expression \(2x^2 - 3x - 20\), we can follow these steps in order:
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Identify the coefficients: Recognize \(a = 2\), \(b = -3\), and \(c = -20\) from the expression in the form \(ax^2 + bx + c\).
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Multiply \(a\) and \(c\): Calculate \(a \cdot c = 2 \cdot (-20) = -40\).
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Find two numbers that multiply to \(ac\) and add to \(b\): Look for two numbers that multiply to \(-40\) and add to \(-3\). The numbers are \(5\) and \(-8\) since \(5 \cdot (-8) = -40\) and \(5 + (-8) = -3\).
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Rewrite the middle term using the two numbers found: Rewrite \(-3x\) as \(5x - 8x\). Thus, the expression becomes: \[ 2x^2 + 5x - 8x - 20 \]
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Group the terms: Group the terms into two pairs: \[ (2x^2 + 5x) + (-8x - 20) \]
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Factor out the greatest common factor (GCF) from each group:
- From the first group \(2x^2 + 5x\), factor out \(x\): \[ x(2x + 5) \]
- From the second group \(-8x - 20\), factor out \(-4\): \[ -4(2x + 5) \]
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Combine the factored terms: Now, combine the factors: \[ x(2x + 5) - 4(2x + 5) = (2x + 5)(x - 4) \]
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Final expression: The final factored form of the expression is: \[ (2x + 5)(x - 4) \]
So, the steps in order are:
- Identify coefficients.
- Multiply \(a\) and \(c\).
- Find two numbers that multiply to \(ac\) and add to \(b\).
- Rewrite the middle term using the two numbers found.
- Group the terms.
- Factor out the GCF from each group.
- Combine the factored terms.
- Write the final factored form.