To find the discriminant of the quadratic function \( f(x) = 3x^2 - 17x - 6 \), we will use the formula for the discriminant, which is given by:
\[ D = b^2 - 4ac \]
where \( a \), \( b \), and \( c \) are the coefficients of the quadratic equation of the form \( ax^2 + bx + c \).
In your case:
- \( a = 3 \)
- \( b = -17 \)
- \( c = -6 \)
Now, we can plug these values into the discriminant formula:
\[ D = (-17)^2 - 4 \cdot 3 \cdot (-6) \] \[ D = 289 + 72 \] \[ D = 289 + 72 = 361 \]
So, the discriminant is:
\[ \boxed{361} \]
Part 2: Determine the number of real solutions
Now, to determine whether there are 0, 1, or 2 real solutions to \( f(x) = 0 \):
- If \( D > 0 \), there are 2 real solutions.
- If \( D = 0 \), there is 1 real solution.
- If \( D < 0 \), there are 0 real solutions.
Since the discriminant \( D = 361 \) is greater than 0, we conclude that there are:
\[ \text{2 real solutions.} \]