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Question

Solve using substitution.

–10x + 3y = 16
y = –8

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Answer 1

To solve the system of equations using substitution, we have:

1. \(-10x + 3y = 16\)
2. \(y = -8\)

Since the second equation already gives us the value of \(y\), we can substitute \(y = -8\) into the first equation.

Substituting \(y\) into the first equation:

\[ -10x + 3(-8) = 16 \]

Calculating \(3(-8)\):

\[ -10x - 24 = 16 \]

Next, we isolate the term with \(x\):

\[ -10x = 16 + 24 \]

\[ -10x = 40 \]

Now, divide by -10:

\[ x = \frac{40}{-10} = -4 \]

Now we have both \(x\) and \(y\):

\[ x = -4, \quad y = -8 \]

Thus, the solution to the system of equations is:

\[ \boxed{(-4, -8)} \]