or Read this word problem. The temperature on February 2 in Lake City was 14°F. The temperature in Ellenville the same day was – 6°F. How much warmer was it in Lake City than in Ellenville? To solve the problem, Gabby subtracted 14–( – 6) and came up with an answer of 8°F. Is Gabby correct? Why or why not?

Question

GPT-4o mini · Answer

To find out how much warmer it was in Lake City than in Ellenville, we need to compare the two temperatures directly.

The temperature in Lake City is 14°F, and the temperature in Ellenville is -6°F. To determine how much warmer Lake City is compared to Ellenville, we can find the difference between the two temperatures:

Calculate the difference: \[ 14 - (-6) \] The expression \( -(-6) \) is the same as \( +6 \), so this becomes: \[ 14 + 6 = 20 \]

So, it was 20°F warmer in Lake City than in Ellenville.

Gabby’s calculation of 14 - (-6) resulting in 8°F is incorrect because she performed the wrong operation. The correct operation yields a temperature difference of 20°F.

Hexx · Answer

his word problem. A dolphin was swimming 7 meters below the surface of the ocean. It located a squid and dove down 4 more meters to eat it. What is the location of the dolphin now relative to the surface? To solve the problem, Lamar subtracted – 7–( – 4) and came up with an answer of – 3 meters. Is Lamar correct? Why or why not?

GPT-4o mini · Answer

To determine the location of the dolphin relative to the surface after it dives down, we need to consider its starting depth and the additional depth it dived.

The dolphin starts at a depth of 7 meters below the surface, which we can express as -7 meters.
It then dives down an additional 4 meters. Since this is deeper, we should subtract 4 from -7.

So we calculate the total depth as follows: \[ -7 - 4 = -11 \text{ meters} \]

This means the dolphin is now 11 meters below the surface of the ocean.

Lamar's calculation involved the expression \( -7 - (-4) \), which is not aligned with the problem's requirements. This expression incorrectly suggested that the dolphin was moving upwards instead of downwards. If he had computed it correctly as \( -7 - 4 \), he would have arrived at -11 meters, indicating the correct position of the dolphin.

So, Lamar is not correct because he did not apply the depth addition properly, leading to an incorrect answer of -3 meters instead of -11 meters.

Hexx · Answer

Kylie is studying the change in the water level of Sweetgum Pond as part of a summer science experiment. In the first week of June, the change in the water level was – 4 centimeters. The next week it stormed almost every day, so the water level rose 7 centimeters. What was the change in the water level over the first two weeks of June?

GPT-4o mini · Answer

To find the total change in the water level over the first two weeks of June, we need to combine the changes in water level for both weeks.

First week of June: The change in water level was -4 centimeters (which means the water level decreased by 4 cm).
Second week of June: The change in water level was +7 centimeters (meaning the water level increased by 7 cm).

Now, we can calculate the total change by adding these two changes together:

\[ \text{Total change} = -4 + 7 \] \[ \text{Total change} = 3 \text{ centimeters} \]

So, the overall change in the water level over the first two weeks of June was +3 centimeters. This means that, after both weeks, the water level rose a total of 3 centimeters.

Hexx · Answer

When Ava went to bed, the temperature was 3°F. When she woke up, the temperature had decreased by 6°F. What was the temperature when Ava woke up? °F

GPT-4o mini · Answer

To find the temperature when Ava woke up, we start with the initial temperature and then subtract the decrease in temperature.

Initial temperature: 3°F
Decrease in temperature: 6°F

Now, we perform the calculation:

\[ \text{Temperature when Ava woke up} = 3°F - 6°F \]

Calculating this gives:

\[ 3 - 6 = -3°F \]

Therefore, the temperature when Ava woke up was -3°F.