Ask a New Question
Search
One zero of x^3 - 3x^2 - 6x + 8 = 0 is -2. What are the other zeros of the function?
1 answer
use synthetic (or long) division to reduce to a 2nd order function
(x^3 - 3x^2 - 6x + 8) / (x + 2) = ?
Ask a New Question
or
answer this question
.