One week before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×10^3 visits were reflected in their logbook during this one-week period, while only about 5×10^2 were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.(1 p??oint) times

Answer 1

To find how many times higher the number of library visits before examination day is compared to the average weekly visits, we need to divide the number of visits before the examination by the average number of visits.

The number of visits before the examination is approximately \( 2 \times 10^3 \) and the average number of visits in a week is \( 5 \times 10^2 \).

Now, we perform the calculation:

\[ \frac{2 \times 10^3}{5 \times 10^2} \]

First, we can simplify the fraction:

\[ = \frac{2}{5} \times \frac{10^3}{10^2} \]

\[ = \frac{2}{5} \times 10^{3-2} \]

\[ = \frac{2}{5} \times 10^1 \]

\[ = \frac{2}{5} \times 10 = 4 \]

Thus, the number of library visits before examination day is 4 times higher than the number of visits in an average week.

The final answer is:

\[ \boxed{4} \]