One week before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×10^3

Question

visits were reflected in their logbook during this one-week period, while only about 5×10^2
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.(1 point)
times

Answer 1

To find out how many times higher the number of library visits one week before the examination day is compared to the average visits in a week, we can divide the number of visits before the examination by the average number of visits.

Given:

• Number of visits before examination = \(2 \times 10^3\)
• Average number of visits = \(5 \times 10^2\)

Now, calculate:

\[ \text{Number of times higher} = \frac{2 \times 10^3}{5 \times 10^2} \]

This simplifies to:

\[ = \frac{2}{5} \times \frac{10^3}{10^2} \]

\[ = \frac{2}{5} \times 10^{3-2} \]

\[ = \frac{2}{5} \times 10^1 \]

\[ = \frac{2 \times 10}{5} \]

\[ = \frac{20}{5} = 4 \]

Therefore, the number of library visits before examination day is 4 times higher than the average number of visits in a week.