To determine which equation has the solution of the lowest value, we need to solve each equation for \( x \).
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Equation 1: \( x + 25 = 2 \) \[ x = 2 - 25 \] \[ x = -23 \]
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Equation 2: \( x - 7 = 28 \) \[ x = 28 + 7 \] \[ x = 35 \]
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Equation 3: \( x - 6 = -16 \) \[ x = -16 + 6 \] \[ x = -10 \]
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Equation 4: \( x + 19 = -5 \) \[ x = -5 - 19 \] \[ x = -24 \]
Now, we have the solutions:
- Equation 1: \( x = -23 \)
- Equation 2: \( x = 35 \)
- Equation 3: \( x = -10 \)
- Equation 4: \( x = -24 \)
Among these, the lowest value is \( -24 \) from the fourth equation, \( x + 19 = -5 \).
So, the equation with the solution of the lowest value is \( x + 19 = -5 \).