One student calibrated a 50-mL burette by using the mass of water delivered. The student used an analytical balance which was previously calibrated by STEEL (density = 7.8 g/mL). During calibration, the temperature of water was found to be 19.0oC. The density of water at this temperature is 0.9984 g/mL. The results of the calibration by the student is shown in the table below:
A B C D E
Apparent burette reading, mL 10.05 20.04 30.08 40.07 49.98
Weight H2O delivered, g 10.03 20.09 30.05 40.02 49.83
Questions:
What is the true mass of water delivered in A?
A) 10.03 B) 10.04 C) 10.05 D) 10.06 E) 10.07
What is the true mass of water delivered in B?
A) 20.12 B) 20.13 C) 20.14 D) 20.15 E) 20.16
What is the true mass of water delivered in C?
A) 30.13 B) 30.11 C) 30.10 D) 30.09 E) 30.08
What is the true mass of water delivered in D?
A) 40.09 B) 40.08 C) 40.07 D) 40.06 E) 40.05
What is the true volume of water delivered in A?
A) 10.00 B) 10.02 C) 10.04 D) 10.06 E) 10.08
What is the true volume of water delivered in B?
A) 20.12 B) 20.14 C) 20.16 D) 20.18 E) 20.20
What is the true volume of water delivered in D?
A) 40.11 B) 40.12 C) 40.13 D) 40.14 E) 40.15
What is the true volume of water delivered in E?
A) 50.00 B) 49.98 C) 49.96 D) 49.94 E) 49.92
What is the correction volume of water delivered in C?
A) 0.04 B) 0.08 C) 0.00 D) -0.04 E) -0.08
What is the true volume of water delivered in D?
A) 0.11 B) 0.12 C) 0.13 D) 0.14 E) 0.15
4 answers
Two questions:
1. For the Apparent burette reading of 10.05 and the others. I don't get it. What does "apparent burette reading" mean? How can 10.05, for example, be an apparent reading. It either read 10.05 or it didn't.
2. This looks like a question I dealt with in while in school about 70 years ago. It was all about air bouancy and how to calibrate a balance. We had to make corrections depending upon the weights; i.e., were they stainless, aluminum, bronze, etc. So what can you tell me about your class, the subject, what you are studying. what level, etc.
It's not clear what apparent reading or true weight are. If the answers are posted that the author believes are the correct answwer, than maybe someone can help you figure out why the answer is what it is, or help you in understanding why the answer key is incorrect.