Let's start by letting M be the total amount of money raised in the harambee.
One-seventh of the money, (1/7)*M, was used to renovate a staff house.
The remainder after renovating the staff house is M - (1/7)*M = (6/7)*M
Two-thirds of this remainder, (2/3)*((6/7)*M), was used for the construction of a classroom.
The amount of money that remained after the construction of the classroom is (6/7)*M - (2/3)*((6/7)*M) = (6/7)*M - (2/3)*(6/7)*M = (6/7)*M - (4/7)*M = (2/7)*M
We are given that this remaining amount is kshs.630,000.
So (2/7)*M = 630,000
To find M, we can multiply both sides of the equation by (7/2):
M = 630,000 * (7/2) = 2,205,000
Therefore, the total amount that was raised in the harambee was kshs.2,205,000.
One_seventh of the money that was raised in a school harambee was used to renovate a staff house while two_thirds of the remainder was used for construction of a classroom .If kshs.630000remained still,calculate the much that was raised
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